Concentrations 82563

In the hospital laboratory, two containers contained different concentrations of alcohol. After mixing 10 liters of alcohol from the first container with 14 liters from the second container, 75% of the alcohol was formed. If 40 liters from the first container were mixed with 8 liters from the second container, 70% of alcohol would be formed. What percentage of alcohol was in the containers?

Correct answer:

a =  68 %
b =  80 %

Step-by-step explanation:

r1=75%=10075=43=0.75 r2=70%=10070=107=0.7  10 a/100+14b/100 = 75/100(10+14) 40 a/100+8b/100 = 70/100 (40+8)  10 a+14b=75(10+14) 40 a+8b=70 (40+8)  10 a+14 b=75 (10+14) 40 a+8 b=70 (40+8)  10a+14b=1800 40a+8b=3360  Pivot:Row1Row2 40a+8b=3360 10a+14b=1800  Row24010 Row1Row2 40a+8b=3360 12b=960  b=12960=80 a=4033608b=4033608 80=68=68%  a=68 b=80



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