Dilution

How many litres of water will have to be added to 1,125 litres of a 45% acid solution so that the resulting mixture contains more than 25% but less than 30% acid?

Final Answer:

V1 =  562.5 l
V2 =  900 l

Step-by-step explanation:

V0​=1125 l c1​=45%=10045​=209​=0.45 c2​=30%=10030​=103​=0.3 c3​=25%=10025​=41​=0.25  V1​ ≤ V ≤ V2​  c1​⋅ V0​=c2​⋅ (V0​+V1​) 0.45⋅ 1125=0.3⋅ (1125+V1​)  0.3V1​=168.75  V1​=0.3168.75​=562.5  V1​=21125​≐562.5=562.5 l
c1​⋅ V0​=c3​⋅ (V0​+V2​) 0.45⋅ 1125=0.25⋅ (1125+V2​)  0.25V2​=225  V2​=0.25225​=900  V2​=900=900 l

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You need to know the following knowledge to solve this word math problem:

algebrabasic operations and conceptsUnits of physical quantitiesthemes, topicsGrade of the word problem

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