# Cube

Calculate the surface of the cube ABCDA'B'C'D' if the area of rectangle ACC'A' = 344 mm2.

Correct result:

S =  1459.468 mm2

#### Solution:

$S_{1}=344 \ \\ S_{1}=a \cdot \ a \cdot \ \sqrt{ 2 } \ \\ a=\sqrt{ S_{1}/\sqrt{ 2 } }=\sqrt{ 344/\sqrt{ 2 } } \doteq 15.5963 \ \\ S=6 \cdot \ a^2=6 \cdot \ 15.5963^2=1032 \ \sqrt{ 2 }=1459.468 \ \text{mm}^2$

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