Cube

Calculate the surface of the cube ABCDA'B'C'D' if the area of rectangle ACC'A' = 344 mm2.

Correct result:

S =  1459.468 mm2

Solution:

S1=344 S1=a a 2 a=S1/2=344/215.5963 S=6 a2=6 15.59632=1032 2=1459.468 mm2S_{1}=344 \ \\ S_{1}=a \cdot \ a \cdot \ \sqrt{ 2 } \ \\ a=\sqrt{ S_{1}/\sqrt{ 2 } }=\sqrt{ 344/\sqrt{ 2 } } \doteq 15.5963 \ \\ S=6 \cdot \ a^2=6 \cdot \ 15.5963^2=1032 \ \sqrt{ 2 }=1459.468 \ \text{mm}^2



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Pythagorean theorem is the base for the right triangle calculator.
See also our trigonometric triangle calculator.

 
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