# Tereza

The cube has area of base 256 mm2.

Calculate the edge length, volume and area of its surface.

Result

a =  16 mm
V =  4096 mm3
S2 =  1536 mm2

#### Solution:

$S=256 \ \text{mm}^2 \ \\ S=a^2=a \cdot \ a \ \\ a=\sqrt{ S }=\sqrt{ 256 }=16 \ \text{mm}$
$V=S \cdot \ a=256 \cdot \ 16=4096 \ \text{mm}^3$
$S_{2}=6 \cdot \ S=6 \cdot \ 256=1536 \ \text{mm}^2$

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