The tetrahedron

Calculate the surface area and volume of a regular tetrahedron 4.9 cm high, the base edge has a length of 6 cm.

Correct answer:

S =  62.35 cm2
V =  25.46 cm3

Step-by-step explanation:

h=4.9 cm a=6 cm  h12=a2(a/2)2  h1=32 a=32 6=3 3 cm5.1962 cm  S1=a h12=6 5.19622=9 3 cm215.5885 cm2  S=4 S1=4 15.5885=36 3=62.35 cm2
 a2=h2+(2/3 h1)2  h=a2(2/3 h1)2=62(2/3 5.1962)2=2 6 cm4.899 cm  V=13 S1 h=13 15.5885 4.899=18 2=25.46 cm3



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