Rectangular field

One dimension of the rectangular field is 168 m greater than the second dimension. If each side of the rectangle increases by 9 m increases, the surface field is 2187 m². Find dimensions of the field.

Final Answer:

x =  201 m
y =  33 m

Step-by-step explanation:

$$\begin{gathered} \Delta S=2187{\text{m}}^2 \\ x=y+168\text{m} \\ {S}_1-S_2=\Delta S \\ (x+9)(y+9)-xy=\Delta S \\ (x+9)\cdot ((x-168)+9)-x\cdot (x-168)=2187 \\ 18x=3618 \\ x=\frac{3618}{18}=201 \\ x=201=201\text{m} \end{gathered}$$

$y=x-168=201-168=33\text{m}$

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