Tree shadow 3

What is the diameter of a tree wrapped in a rope around 3 m 9 dm 7 cm long? How big is its cross-sectional area?

Final Answer:

D =  1.2637 m
S =  1.2542 m2

Step-by-step explanation:

o=3+9/10+7/100=100397=3.97 m o = π D  m D=o/π=3.97/3.1416=1.2637 m
r=D/2=1.2637/20.6318 m S=π r2=3.1416 0.63182=1.2542 m2



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