What is the diameter of a tree around which is 3m 9dm 7cm long rope wrapped? How big is its cross-sectional area?

Correct result:

D =  1.264 m
S =  1.255 m2

#### Solution:

$o=3+9/10+7/100=\dfrac{ 397 }{ 100 }=3.97 \ \text{m} \ \\ o=\pi \cdot \ D \ \\ D=o/\pi=3.97/3.1416=1.264 \ \text{m}$
$r=D/2=1.2637/2=\dfrac{ 79 }{ 125 }=0.632 \ \text{m} \ \\ S=\pi \cdot \ r^2=3.1416 \cdot \ 0.632^2=1.255 \ \text{m}^2$

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