Calculate what member of the sequence specified by
{4n2+85} \{ 4^{n-2}+85 \}
has value 86.

Correct result:

n =  2


4n2+85=86 4n2=1 (n2)ln(4)=ln(1) n=2+ln(1)ln(4) n=24^{n-2}+85 = 86 \ \\ 4^{n-2} = 1 \ \\ (n-2)\ln(4) = \ln(1) \ \\ n = 2 + \dfrac{ \ln(1)}{ \ln(4)} \ \\ n = 2

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