Assignment 34461

The travel agency has reserved 14 triple or quadruple rooms in the hotel for two weeks in July. How many families of three and how many families of four can sign up for the tour if the maximum number of occupied seats in the bus is 50? Assignment and solution.

Correct answer:

a =  6
b =  8

Step-by-step explanation:


a+b=14
3a+4b=50

a+b=14
3·a+4·b=50

a+b = 14
3a+4b = 50

Pivot: Row 1 ↔ Row 2
3a+4b = 50
a+b = 14

Row 2 - 1/3 · Row 1 → Row 2
3a+4b = 50
-0.33b = -2.67


b = -2.66666667/-0.33333333 = 8
a = 50-4b/3 = 50-4 · 8/3 = 6

a = 6
b = 8

Our linear equations calculator calculates it.



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