Hydraulic 35301

The hydraulic jack has pistons with a capacity of 6 cm2 and 360 cm2. How much force do we have to apply to the smaller piston to be able to lift a body weighing 180 kg on the larger piston?

Correct answer:

F1 =  30 N

Step-by-step explanation:

S1=6 cm2 S2=360 cm2  m2=180 kg g=10 m/s2  F2=g m2=10 180=1800 N  p1=p2 F1/S1=F2/S2  F1=F2 S2S1=1800 3606=3601800 6=36010800=30 N

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