Hydraulic blade force

The hydraulic blade has pistons with an area of 10 cm² and 500 cm². How much force acts on the larger piston if we act on the smaller piston with a force of 100 N?

Final Answer:

F2 =  5000 N

Step-by-step explanation:

S1=10 cm2 S2=500 cm2 F1=100 N  p1=p2 F1/S1 = F2/S2  F2=F1 S1S2=100 10500=10100 500=1050000=5000 N



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