Hydraulic 36041

The large piston of the hydraulic system has a capacity of 0.25 m2 and a small 10 cm2. How much force do we exert on the small piston to be lifted by 750 N?

Correct answer:

F2 =  3 N

Step-by-step explanation:

S1=0.25 m2 cm2=0.25 10000  cm2=2500 cm2 S2=10 cm2 F1=750 N  p1=p2 F1/S1 = F2/S2  F2=F1 S1S2=750 250010=2500750 10=25007500=3 N



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