Diver and pressure

Determine what pressures is exposed diver without a suit at a depth of 15 meters, with a small space suit at a depth of 25 meters and a massive suit at a depth of 70 m in water.

Result

p1 =  147.15 kPa
p2 =  245.25 kPa
p3 =  686.7 kPa

Solution:

r=1000 g=9.81 p1=r g 15/1000=1000 9.81 15/1000=294320=147.15=147.15  kPa r = 1000 \ \\ g = 9.81 \ \\ p_{ 1 } = r \cdot \ g \cdot \ 15/1000 = 1000 \cdot \ 9.81 \cdot \ 15/1000 = \dfrac{ 2943 }{ 20 } = 147.15 = 147.15 \ \text{ kPa }
p2=r g 25/1000=1000 9.81 25/1000=9814=245.25=245.25  kPa p_{ 2 } = r \cdot \ g \cdot \ 25/1000 = 1000 \cdot \ 9.81 \cdot \ 25/1000 = \dfrac{ 981 }{ 4 } = 245.25 = 245.25 \ \text{ kPa }
p3=r g 70/1000=1000 9.81 70/1000=686710=686.7=686.7  kPa p_{ 3 } = r \cdot \ g \cdot \ 70/1000 = 1000 \cdot \ 9.81 \cdot \ 70/1000 = \dfrac{ 6867 }{ 10 } = 686.7 = 686.7 \ \text{ kPa }



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