Stones in aquarium

In an aquarium with a length of 2 m, 1.5 m wide and 2.5 m deep, the water is up to three-quarters of the depth. Can we place 2m cubic meters of stones in the aquarium without spilling water? (0 = no, 1 = yes)

Result

x =  0

Solution:

a=2 m b=1.5 m c=2.5 m  V=a⋅ b⋅ c=2⋅ 1.5⋅ 2.5=152=7.5 m3 V1=34⋅ V=34⋅ 7.5=458=5.625 m3  V2=V1+2=5.625+2=618=7.625 m3  V2>V x=0a = 2 \ m \ \\ b = 1.5 \ m \ \\ c = 2.5 \ m \ \\ \ \\ V = a \cdot \ b \cdot \ c = 2 \cdot \ 1.5 \cdot \ 2.5 = \dfrac{ 15 }{ 2 } = 7.5 \ m^3 \ \\ V_{ 1 } = \dfrac{ 3 }{ 4 } \cdot \ V = \dfrac{ 3 }{ 4 } \cdot \ 7.5 = \dfrac{ 45 }{ 8 } = 5.625 \ m^3 \ \\ \ \\ V_{ 2 } = V_{ 1 } + 2 = 5.625 + 2 = \dfrac{ 61 }{ 8 } = 7.625 \ m^3 \ \\ \ \\ V_{ 2 }>V \ \\ x = 0

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