Stones in aquarium

In an aquarium with a length of 2 m, 1.5 m wide and 2.5 m deep, the water is up to three-quarters of the depth. Can we place 2m cubic meters of stones in the aquarium without spilling water? (0 = no, 1 = yes)

Correct result:

x =  0

Solution:

a=2 m b=1.5 m c=2.5 m  V=a b c=2 1.5 2.5=152=7.5 m3 V1=34 V=34 7.5=458=5.625 m3  V2=V1+2=5.625+2=618=7.625 m3  V2>V x=0a=2 \ \text{m} \ \\ b=1.5 \ \text{m} \ \\ c=2.5 \ \text{m} \ \\ \ \\ V=a \cdot \ b \cdot \ c=2 \cdot \ 1.5 \cdot \ 2.5=\dfrac{ 15 }{ 2 }=7.5 \ \text{m}^3 \ \\ V_{1}=\dfrac{ 3 }{ 4 } \cdot \ V=\dfrac{ 3 }{ 4 } \cdot \ 7.5=\dfrac{ 45 }{ 8 }=5.625 \ \text{m}^3 \ \\ \ \\ V_{2}=V_{1} + 2=5.625 + 2=\dfrac{ 61 }{ 8 }=7.625 \ \text{m}^3 \ \\ \ \\ V_{2}>V \ \\ x=0



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