Stones in aquarium

In an aquarium with a length of 2 m, 1.5 m wide and 2.5 m deep, the water is up to three-quarters of the depth. Can we place 2m cubic meters of stones in the aquarium without spilling water? (0 = no, 1 = yes)

Correct result:

x =  0

Solution:

$a=2 \ \text{m} \ \\ b=1.5 \ \text{m} \ \\ c=2.5 \ \text{m} \ \\ \ \\ V=a \cdot \ b \cdot \ c=2 \cdot \ 1.5 \cdot \ 2.5=\dfrac{ 15 }{ 2 }=7.5 \ \text{m}^3 \ \\ V_{1}=\dfrac{ 3 }{ 4 } \cdot \ V=\dfrac{ 3 }{ 4 } \cdot \ 7.5=\dfrac{ 45 }{ 8 }=5.625 \ \text{m}^3 \ \\ \ \\ V_{2}=V_{1} + 2=5.625 + 2=\dfrac{ 61 }{ 8 }=7.625 \ \text{m}^3 \ \\ \ \\ V_{2}>V \ \\ x=0$

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