Stones in aquarium

In an aquarium with a length 2 m; width 1.5 m and a depth of 2.5 m is a water level up to three-quarters of the depth. Can we place stones with a volume of 2 m3 into the aquarium without water being poured out?

Result

x=




Solution:

a=2 m b=1.5 m c=2.5 m V1=a b c=2 1.5 2.5=152=7.5 m3 V2=3/4 V1=3/4 7.5=458=5.625 m3 V3=V2+2=5.625+2=618=7.625 m3 V3>V1 x=0



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