Diver

Please calculate using Pascal's law. The window of the diving helmet has a surface content of about 7dm2. Calculate what pressure force acts on the window at a depth of 20 meters below the water surface.

Correct result:

F =  14 kN

Solution:

$$\begin{gathered} S=7{\text{dm}}^2\to {\text{m}}^2=7\mathrm{/}100{\text{m}}^2=0.07{\text{m}}^2 \\ h=20\text{ m } \\ g=10{\text{m/s}}^2 \\ \rho =1000{\text{kg/m}}^3 \\ {F}_1=S\cdot h\cdot g\cdot \rho =0.07\cdot 20\cdot 10\cdot 1000=14000\text{ N } \\ F=F_1\mathrm{/}1000=14000\mathrm{/}1000=14\text{ kN} \end{gathered}$$

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