Diver

Please calculate using Pascal's law. The window of the diving helmet has a surface area of about 7 dm². What pressure force acts on the window at a depth of 20 meters below the water surface?

Final Answer:

F =  14 kN

Step-by-step explanation:

$$\begin{gathered} S=7{\text{dm}}^2\to {\text{m}}^2=7:100{\text{m}}^2=0.07{\text{m}}^2 \\ h=20\text{m} \\ g=10{\text{m/s}}^2 \\ \rho =1000{\text{kg/m}}^3 \\ {F}_1=S\cdot h\cdot g\cdot \rho =0.07\cdot 20\cdot 10\cdot 1000=14000\text{N} \\ F=F_1/1000=14000/1000=14\text{kN} \end{gathered}$$

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