Automatically 20853

Please calculate according to Pascal's law. The depth bomb used against the submarine was equipped with a hydrostat, which automatically caused it to explode at a given depth. The hydrostat was set to a pressure of 400kPa. At what depth below the surface did the bomb explode if the density of seawater was 1030kg per M3?

Final Answer:

h =  39.5871 m

Step-by-step explanation:

$$\begin{gathered} p=400\cdot 1000=400000\text{Pa} \\ \rho =1030{\text{kg/m}}^3 \\ g=9.81{\text{m/s}}^2 \\ p=\rho hg \\ h=\frac{p}{\rho \cdot g}=\frac{400000}{1030\cdot 9.81}=39.5871\text{m} \end{gathered}$$

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