Automatically 20853

Please calculate according to Pascal's law. The depth bomb used against the submarine was equipped with a hydrostat, which automatically caused it to explode at a given depth. The hydrostat was set to a pressure of 400kPa. At what depth below the surface did the bomb explode if the density of seawater was 1030kg per M3?

Correct answer:

h =  39.5871 m

Step-by-step explanation:

p=400 1000=400000 Pa ρ=1030 kg/m3 g=9.81 m/s2   p = ρ h g  h=ρ gp=1030 9.81400000=39.5871 m

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