Kerosene tank force

Please calculate according to Pascal's law. Kerosene in a block-shaped metal tank reaches a height of 180 cm. Calculate the force acting on the bottom with dimensions of 1.5 m and 3 m if the density of kerosene is 820 kg per M3.

Final Answer:

F =  65158.02 N

Step-by-step explanation:

$$\begin{gathered} c=180\text{cm}\to \text{m}=180:100\text{m}=1.8\text{m} \\ a=1.5\text{m} \\ b=3\text{m} \\ \rho =820{\text{kg/m}}^3 \\ V=a\cdot b\cdot c=1.5\cdot 3\cdot 1.8=\frac{81}{10}=8.1{\text{m}}^3 \\ m=\rho \cdot V=820\cdot 8.1=6642\text{kg} \\ g=9.81{\text{m/s}}^2 \\ F=m\cdot g=6642\cdot 9.81=65158.02\text{N} \end{gathered}$$

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