Painting a hut

It is necessary to paint the exterior walls of hut whose layout is a rectangle of 6.16 m x 8.78 m wall height is 2.85 meters. Cottage has five rectangular windows; three have dimensions of 1.15 m x 1.32 m and two 0,45 m x 0.96 m. How many m2 is necessary to paint?

Result

S =  79.74 m2

Solution:

a=6.16 m b=8.78 m c=2.85 m  o=2⋅ a+2⋅ b=2⋅ 6.16+2⋅ 8.78=74725=29.88 m S1=o⋅ c=29.88⋅ 2.85=85.158 m2 S2=3⋅ 1.15⋅ 1.32=4.554 m2 S3=2⋅ 0.45⋅ 0.96=0.864 m2 S=S1−S2−S3=85.158−4.554−0.864=398750=79.74 m2a=6.16 \ \text{m} \ \\ b=8.78 \ \text{m} \ \\ c=2.85 \ \text{m} \ \\ \ \\ o=2 \cdot \ a+2 \cdot \ b=2 \cdot \ 6.16+2 \cdot \ 8.78=\dfrac{ 747 }{ 25 }=29.88 \ \text{m} \ \\ S_{1}=o \cdot \ c=29.88 \cdot \ 2.85=85.158 \ \text{m}^2 \ \\ S_{2}=3 \cdot \ 1.15 \cdot \ 1.32=4.554 \ \text{m}^2 \ \\ S_{3}=2 \cdot \ 0.45 \cdot \ 0.96=0.864 \ \text{m}^2 \ \\ S=S_{1} - S_{2} - S_{3}=85.158 - 4.554 - 0.864=\dfrac{ 3987 }{ 50 }=79.74 \ \text{m}^2

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