Right triangle

It is given a right triangle
angle alpha of 90 degrees
beta angle of 55 degrees
c = 10 cm
use Pythagorean theorem to calculate sides a and b


Result

a =  17.434 cm
b =  14.281 cm

Solution:

$c=10 \ \\ B=55 \ \\ a^2=b^2+c^2 \ \\ \cos(B)=c/a \ \\ a=c / \cos( 55 ^\circ \rightarrow\ \text{rad} )=c / \cos( 55 ^\circ \cdot \ \dfrac{ \pi }{ 180 } \ )=10 / \cos( 55 ^\circ \cdot \ \dfrac{ 3.1415926 }{ 180 } \ )=17.43447=17.434 \ \text{cm}$

$b=\sqrt{ a^2-c^2 }=\sqrt{ 17.4345^2-10^2 } \doteq 14.2809 \doteq 14.281 \ \text{cm}$

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