Fifth member

Determine the fifth member of the arithmetic progression, if the sum of the second and fifth members equal to 73, and difference d = 7.

Correct result:

a5 =  47

Solution:

$a_{2}+a_{5}=73 \ \\ d=7 \ \\ a_{1}+d+a_{1}+4d=73 \ \\ a_{1}=(73-5 \cdot \ d)/2=(73-5 \cdot \ 7)/2=19 \ \\ a_{5}=a_{1}+4 \cdot \ d=19+4 \cdot \ 7=47$

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