Consecutive 46781

We get three consecutive GP members if we subtract the same number from 33, 45, and 63. Determine this GP and calculate its fifth member.

Correct answer:

a1 =  24
q =  1.5
a5 =  121.5

Step-by-step explanation:

b1=33 b2=45 b3=63  a1 = b1d a2 = b2d = q a1 a3 = b3d = q2 a1  b2d = q (b1d) b3d = q2 (b1d)  q = (b2d)/(b1d)  b3d = (b2d)/(b1d) (b2d)/(b1d) (b1d) (b3d) (b1d) = (b2d) (b2d)   (b3d) (b1d) = (b2d) (b2d)  6d+54=0  6 d+54=0  6d=54  d=654=9  d=9  q=(b2d)/(b1d)=(459)/(339)=23=121=1.5  a1=b1d=339=24
q=1.5=23=121  Verifying Solution:  a2=b2d=459=36 a3=b3d=639=54  A1=a1=24 A2=q A1=1.5 24=36 A3=q A2=1.5 36=54
a5=a1 q4=24 1.54=121.5



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