Consecutive 46781

We get three consecutive GP members if we subtract the same number from 33, 45, and 63. Determine this GP and calculate its fifth member.

Correct answer:

a1 =  24
q =  1.5
a5 =  121.5

Step-by-step explanation:

b1=33 b2=45 b3=63  a1=b1d a2=b2d=q a1 a3=b3d=q2 a1  b2d=q (b1d) b3d=q2 (b1d)  q=(b2d)/(b1d)  b3d=(b2d)/(b1d) (b2d)/(b1d) (b1d) (b3d) (b1d)=(b2d) (b2d)  (b3d) (b1d)=(b2d) (b2d)  6d+54=0  6 d+54=0  6d=54  d=654=9  d=9  q=(b2d)/(b1d)=(459)/(339)=23=121=1.5  a1=b1d=339=24
a5=a1 q4=24 1.54=121.5

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