The base 2

The base diameter of a right cone is 16cm and it's slant height is 12cm.
A. ) Find the perpendicular height of the cone to 1 decimal place.
B. ) Find the volume of the cone, convert to 3 significant figure. Take pie =3.14

Correct result:

h =  8.9 cm
V =  599.451 cm³

Solution:

$$\begin{gathered} D=16\text{ cm } \\ s=12\text{ cm } \\ r=D\mathrm{/}2=16\mathrm{/}2=8\text{ cm } \\ {s}^2=r^2+h^2 \\ h=\sqrt{s^2-r^2}=\sqrt{12^2-8^2}=4\sqrt{5}=8.9\text{ cm} \end{gathered}$$

$V={\displaystyle \frac{1}{3}}\cdot \pi \cdot r^2\cdot h={\displaystyle \frac{1}{3}}\cdot 3.1416\cdot 8^2\cdot 8.9443=599.451{\text{cm}}^3$

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