Admission 38691

In one HA class, there were 8 more pupils in the first group than in the second group. After the admission of two new pupils to each of the groups, there were twice as many pupils in the 1st group as in the 2nd group. How many pupils were there in each group?

Correct answer:

a =  14
b =  6

Step-by-step explanation:

a+2 = 2·(b+2)

a-b = 8
a-2b = 2

Row 2 - Row 1 → Row 2
a-b = 8
-b = -6

b = -6/-1 = 6
a = 8+b = 8+6 = 14

a = 14
b = 6

Our linear equations calculator calculates it.

Did you find an error or inaccuracy? Feel free to write us. Thank you!

Tips for related online calculators
Do you have a system of equations and looking for calculator system of linear equations?

You need to know the following knowledge to solve this word math problem:

Related math problems and questions: