The mowers

The mowers were to mow two meadows, one twice as big as the other. They divided into two equal groups in the first half of the day. One continued to mow a larger meadow and cut it all by the end of the day. The second group mowed a smaller meadow but did not mow it all until the end of the day. The mowers cut the rest the next day, and one mower is used for the whole day. How many mowers were there? (We assume that the mowing time in the first and second half of the day was the same, and the mowing power was the same. )

Final Answer:

n =  8

Step-by-step explanation:

$$\begin{gathered} S_1=2S_2 \\ n/2\cdot 1+n/2\cdot (1/2)=S_1 \\ n/2\cdot 1/2+1\cdot 1=S_2 \\ n/2\cdot 1+n/2\cdot (1/2)=2S_2 \\ n/2\cdot 1/2+1\cdot 1=S_2 \\ n/2\cdot 1+n/2\cdot (1/2)=2S_2 \\ \frac{n}{2}\cdot \frac{1}{2}+1\cdot 1=(\frac{n}{2}\cdot 1+\frac{n}{2}\cdot (\frac{1}{2}))/2 \\ n/2\cdot 1/2+1\cdot 1=(n/2\cdot 1+n/2\cdot (1/2))/2 \\ 0.25n=2 \\ n=\frac{2}{0.25}=8 \\ n=8 \end{gathered}$$

Try another example