The sum

The sum of the squares of two immediately following natural numbers is 1201. Find these numbers.

Correct result:

a =  24
b =  25


2x2=1201 x=1201/224.5051 x1=x=24.5051=24 x2=x=24.5051=25  a2+(a+1)2=1201  2a2+2a1200=0  p=2;q=2;r=1200 D=q24pr=2242(1200)=9604 D>0  a1,2=q±D2p=2±96044 a1,2=2±984 a1,2=0.5±24.5 a1=24 a2=25   Factored form of the equation:  2(a24)(a+25)=0  a=a1=24

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