Efficiency 4073

Determine the efficiency of a vacuum cleaner with a power input of 1.2 kW when the suction power is 360 W.

Correct answer:

e =  30 %

Step-by-step explanation:

P=360 W Q=1.2 kW W=1.2 1000  W=1200 W  e=100 QP=100 1200360=1200100 360=120036000=30%



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