Efficiency 35023

The cellar, which has a floor area of ​​50 m2, 3 m below ambient level, was flooded with water to a height of 80 cm. How long does it take for a pump with a power input of 1 kW and an efficiency of 75% (η = 0.75) to drain the water?

Correct answer:

t =  0.4444 h

Step-by-step explanation:

S=50 m2 c=80 cm m=80:100  m=0.8 m h=3 m  V=S c=50 0.8=40 m3 ρ=1000 kg/m3  m=ρ V=1000 40=40000 kg g=10 m/s2  W=m g h=40000 10 3=1200000 J P1=1 kW W=1 1000  W=1000 W η=0.75  P2=η P1=0.75 1000=750 W  P = W/t  t1=W/P2=1200000/750=1600 s t=t1 h=t1:3600  h=1600:3600  h=0.444 h=0.4444 h



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