# Trapezoid

Calculate area of trapezoid ABCD with sides |AD|= 68 cm, |DC|=35 cm, |CB|=12 cm, |AB|=35 cm..

Result

A =  840 cm2

#### Solution:

$\ \\ s = \dfrac{ 68 - 12 + 35 + 35 }{2 } = 63 \ cm \ \\ S_1 = \sqrt{s(s-56)(s-35)(s-35) } = 588 \ cm^2 \ \\ v = \dfrac{ 2 S_1}{ 68 - 12} = 21 \ cm \ \\ A = \dfrac{ 68 + 12}{2} \cdot v = 840 \ \text{cm}^2$

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