Two dice

We roll two dice. What is the probability that the sum of the falling numbers is greater than 3?

Correct answer:

p =  0.9167

Step-by-step explanation:

$$\begin{gathered} 1+1 \\ 1+2 \\ 2+1 \\ {p}_1={\displaystyle \frac{3}{6\cdot 6}}={\displaystyle \frac{1}{12}}\doteq 0.0833 \\ p=1-p_1=1-0.0833={\displaystyle \frac{11}{12}}=0.9167 \end{gathered}$$

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