Sum on dice

We have two dice. What is the greater likelihood of fall a total sum 7 or 8 ? (write 7, 8 or 0 if the probabilities are the same)?

Result

x =  7

Solution:

7=1+6=2+5=3+4=4+3=5+2=6+1 8=2+6=3+5=4+4=5+3=6+2 p1>p2 x=77=1+6=2+5=3+4=4+3=5+2=6+1 \ \\ 8=2+6=3+5=4+4=5+3=6+2 \ \\ p_{1}>p_{2} \ \\ x=7

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Leave us a comment of this math problem and its solution (i.e. if it is still somewhat unclear...):

Showing 3 comments:
#
Math student
7=1+6=2+5=3+4=4+3=5+2=6+1
8=2+6=3+5=4+4=5+3=6+2
p1>p2
x=7

#
Dr Math
hmmm, so we have 8 = 4+4 = 4+4 (thus one less variation than 7)

#
Jay
i dont think so

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