Probabilities 71194

We have a dummy die where numbers fall with probabilities P (1)=0.1; P (2)=0.2; P (3)=0.22; P (4)=0.16; P (5)=0.24; P (6)=0.08. Determine the probability that the two tosses the same numbers.

Correct answer:

p =  0.188

Step-by-step explanation:

p1=0.1 p2=0.2 p3=0.22 p4=0.16 p5=0.24 p6=0.08  p=p12+p22+p32+p42+p52+p62=0.12+0.22+0.222+0.162+0.242+0.082=25047=0.188   Verifying Solution:   p0=610.1667  p8=6 p02=6 612=610.1667

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