Probabilities 71194

We have a dummy die where numbers fall with probabilities P (1)=0.1; P (2)=0.2; P (3)=0.22; P (4)=0.16; P (5)=0.24; P (6)=0.08. Determine the probability that the two tosses the same numbers.

Correct answer:

p =  0.188

Step-by-step explanation:

p1=0.1 p2=0.2 p3=0.22 p4=0.16 p5=0.24 p6=0.08  p=p12+p22+p32+p42+p52+p62=0.12+0.22+0.222+0.162+0.242+0.082=25047=0.188   Verifying Solution:   p0=610.1667  p8=6 p02=6 612=610.1667



Did you find an error or inaccuracy? Feel free to write us. Thank you!



Showing 1 comment:
Zee
I like this so much!





Tips for related online calculators
Need help calculating sum, simplifying, or multiplying fractions? Try our fraction calculator.
Would you like to compute the count of combinations?

You need to know the following knowledge to solve this word math problem:

Related math problems and questions: