Two doctors

Doctor A will determine the correct diagnosis with a probability 93% and doctor B with a probability 79%. Calculate probability of correct diagnosis if patient is diagnosed by both doctors.

Result

p =  98.53 %

Solution:

q1=93%=93100=0.93 q2=79%=79100=0.79  q=q1+q2q1 q2=0.93+0.790.93 0.79=0.9853  p=100 q=100 0.9853=9853100=98.53=98.53%q_{1}=93 \%=\dfrac{ 93 }{ 100 }=0.93 \ \\ q_{2}=79 \%=\dfrac{ 79 }{ 100 }=0.79 \ \\ \ \\ q=q_{1} + q_{2} - q_{1} \cdot \ q_{2}=0.93 + 0.79 - 0.93 \cdot \ 0.79=0.9853 \ \\ \ \\ p=100 \cdot \ q=100 \cdot \ 0.9853=\dfrac{ 9853 }{ 100 }=98.53=98.53 \%



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