Car overtaking

From place A, the cyclist drove at a speed of 24 km/h. They sent a car behind him an hour later, traveling at 60 km/h. When and how far from place A will a cyclist travel?

Final Answer:

t =  0.6667 h
s =  40 km

Step-by-step explanation:

$$\begin{gathered} s_1=s_2 \\ {v}_1=24\text{km/h} \\ {v}_2=60\text{km/h} \\ {v}_1\cdot (t+1)=v_2\cdot t \\ 24\cdot (t+1)=60\cdot t \\ 36t=24 \\ t=\frac{24}{36}=0.66666667 \\ t=\frac{2}{3}\doteq 0.666667=0.6667\text{h} \end{gathered}$$

$s=v_2\cdot t=60\cdot 0.6667=40\text{km}$

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