Motorcyclist 7274

At noon, a cyclist left Šumperk for Olomouc at a speed of 20 km/h. Thirty minutes later, a motorcyclist drove up behind him at 60 km/h. At what distance and at what time did the motorcyclist overtake the cyclist?

Result

s =  15 km
t = 12:45 hh:mm Wrong answer

Step-by-step explanation:


s = 20·(t-12)
s = 60·(t-12.50)

s-20t = -240
s-60t = -750

Row 2 - Row 1 → Row 2
s-20t = -240
-40t = -510


t = -510/-40 = 12.75
s = -240+20t = -240+20 · 12.75 = 15

s = 15
t = 51/4 = 12.75

Our linear equations calculator calculates it.
t=12.75=451=12:45 hh:mm



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