The cyclist

The cyclist drove from A to B, 60 km away. The first half drove at 30km/h, the second at 20km/h. How long did it take for him?

Result

t =  2.5 h

Solution:

s=60 km v1=30 km/h v2=20 km/h  s1=s/2=60/2=30 km  t1=s1/v1=30/30=1 h t2=s1/v2=30/20=32=1.5 h  t=t1+t2=1+1.5=52=2.5 hs=60 \ \text{km} \ \\ v_{ 1 }=30 \ \text{km/h} \ \\ v_{ 2 }=20 \ \text{km/h} \ \\ \ \\ s_{ 1 }=s/2=60/2=30 \ \text{km} \ \\ \ \\ t_{ 1 }=s_{ 1 }/v_{ 1 }=30/30=1 \ \text{h} \ \\ t_{ 2 }=s_{ 1 }/v_{ 2 }=30/20=\dfrac{ 3 }{ 2 }=1.5 \ \text{h} \ \\ \ \\ t=t_{ 1 }+t_{ 2 }=1+1.5=\dfrac{ 5 }{ 2 }=2.5 \ \text{h}

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