Motorcyclist 8375

The distance from point A to point B is 40 km. And a cyclist left at 9:00 a.m. at a speed of 20 km/h. At 9:30 a.m., a motorcyclist drove against him from place B at 40 km/h. At what time and at what distance from A do they meet?


t = 10:00 hh:mm Wrong answer
s1 =  20 km

Step-by-step explanation:

40 = 20(t-9.00) + 40(t-9.50)

40 = 20·(t-9.00) + 40·(t-9.50)

60t = 600

t = 600/60 = 10

t = 10

Our simple equation calculator calculates it.
s = 20 (t19.00) s1=20 (10.009.00)=20 km

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