Two cyclists

Two cyclists started from crossing in the same time. One goes to the north speed 20 km/h, the second eastward at speed 26 km/h. What will be the direct distance cycling 30 minutes from the start?

Result

s =  16.401 km

Solution:

A=90 t=30/60=12=0.5 a=20 t=20 0.5=10 b=26 t=26 0.5=13 s=a2+b2=102+13226916.401216.401 kmA=90^\circ \ \\ t=30/60=\dfrac{ 1 }{ 2 }=0.5 \ \\ a=20 \cdot \ t=20 \cdot \ 0.5=10 \ \\ b=26 \cdot \ t=26 \cdot \ 0.5=13 \ \\ s=\sqrt{ a^2+b^2 }=\sqrt{ 10^2+13^2 } \doteq \sqrt{ 269 } \doteq 16.4012 \doteq 16.401 \ \text{km}



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