Movement

From the crossing of two perpendicular roads started two cyclists (each at the different road). One runs at average speed 28 km/h, the second at average speed 24 km/h. Determine the distance between them after 45 minutes cycling.

Correct result:

x =  27.6586 km

Solution:

t=45 min h=45/60  h=0.75 h v1=28 km/h v2=24 km/h  s1=v1 t=28 0.75=21 km s2=v2 t=24 0.75=18 km  x=s12+s22=212+182=3 85=27.6586 km



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