Cross road

From the junction of two streets that are perpendicular to each other, two cyclists (each on another street) walked out. One ran 18 km/h and the second 24 km/h. How are they away from

a) 6 minutes,
b) 15 minutes?

Correct result:

a =  3 km
b =  7.5 km

Solution:

v1=18 km/h v2=24 km/h  v=v12+v22=182+242=30 km/h t1=6 min h=6/60  h=0.1 h a=t1 v=0.1 30=3 km
t2=15 min h=15/60  h=0.25 h  b=t2 v=0.25 30=152=152 km=7.5 km



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