Two runners

Two runners ran simultaneously towards each other from locations distant 23.1 km. The average speed of the first runner was 1/7 higher than the average speed of the second runner.

How long should each run a 23.1 km, if you know they meet after 58 minutes?

Final Answer:

t1 =  108.7 min
t2 =  124.3 min

Step-by-step explanation:

t=58 min s=23.1 km v=s/t=23.1/58=5802310.3983 km/min  k=1+71=71 7+71=77+71=77+1=781.1429  s1 + s2 = s v1 = v2 (1+1/7) = k v2  v1= k v2 v1+v2 = v  k v2+v2=v 1.1428571428571 v2+v2=0.39827586206897  2.142857v2=0.398276  v2=2.142857140.39827586=0.18586207  v2=29005390.185862  v1=vv2=0.39830.1859=7251540.2124 km/min  t1=t1=s/v1=23.1/0.2124=108.7 min
t2=t2=s/v2=23.1/0.1859=124.3 min



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