Two runners

Two runners ran simultaneously towards each other from locations distant 34.6 km. The average speed of the first runner was 1/5 higher than the average speed of the second runner.

How long should each ran a 34.6 km, if you know that they meet after 67 minutes?

Correct result:

t1 =  122.8 min
t2 =  147.4 min

Solution:

t=67 min s1+s2=34.6 km v1=v2(1+1/5)=1.2v2  v1t+v2t=34.6 v1+v2=34.6/67=0.5164 km/min 2.2v2=0.5164 v2=0.2347 km/min v1=1.2v2=0.2817 km/min  t1=s/v1=34.6/0.2817=122.8 min
t2=s/v2=34.6/0.2347=147.4 min



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