A semi-circular

A semi-circular fishbowl is filled with water and has a diameter of 10 feet. What is the total water weight to the nearest pound in the tank if water weighs 62.5 pounds per cubic foot?

Final Answer:

m =  16362 pd

Step-by-step explanation:

$$\begin{gathered} D=10\text{ft} \\ \rho =62.5{\text{pd/ft}}^3 \\ r=D/2=10/2=5\text{ft} \\ {V}_1=\frac{4}{3}\cdot \pi \cdot r^3=\frac{4}{3}\cdot 3.1416\cdot 5^3\doteq 523.5988{\text{ft}}^3 \\ V=V_1/2=523.5988/2\doteq 261.7994{\text{ft}}^3 \\ m=\rho \cdot V=62.5\cdot 261.7994=16362\text{pd} \end{gathered}$$

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