A semi-circular

A semi-circular fishbowl is filled with water and has a diameter of 10 feet. What is the total weigh of water to the nearest pound in the tank, if water weighs 62.5 pounds per cubic foot?

Correct answer:

m =  16362 pd

Step-by-step explanation:

$$\begin{gathered} D=10\text{ ft } \\ \rho =62.5{\text{pd/ft}}^3 \\ r=D\mathrm{/}2=10\mathrm{/}2=5\text{ ft } \\ {V}_1={\displaystyle \frac{4}{3}}\cdot \pi \cdot r^3={\displaystyle \frac{4}{3}}\cdot 3.1416\cdot 5^3\doteq 523.5988{\text{ft}}^3 \\ V=V_1\mathrm{/}2=523.5988\mathrm{/}2\doteq 261.7994{\text{ft}}^3 \\ m=\rho \cdot V=62.5\cdot 261.7994=16362\text{ pd} \end{gathered}$$

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