Drivers of passenger cars have calculated that at a speed of 60 km/h arrives at destination within 40 minutes. After 20 km refrain five minutes due a technical failure. How fast must go the rest of the way to the finish came at the scheduled time?

Correct result:

v2 =  80 km/h


v1=60 t=40/60=230.6667 h s=v1 t=60 0.6667=40 km s1=20 km  t1=s1/v1=20/60=130.3333 h s2=ss1=4020=20 km t2=tt15/60=0.66670.33335/60=14=0.25 h v2=s2/t2=20/0.25=80 km/h

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