# Triangle ABC

In a triangle ABC side b measure 10 cm less than the side a and side b is half of the side c. Calculate the length of sides if the circumference of the triangle is 42 cm.

Correct result:

a =  18
b =  8
c =  16

#### Solution:

a+b+c=42
b = a-10
b = c/2

a+b+c = 42
a-b = 10
2b-c = 0

a = 18
b = 8
c = 16

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