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How can the total surface of a rectangular pyramid be found if each face is 8 dm high and the base is 10 dm by 6 dm?

Correct answer:

S =  202.0439 dm2

Step-by-step explanation:

a=10 dm b=6 dm h=8 dm  h1​=h2+(b/2)2​=82+(6/2)2​=73​ dm≐8.544 dm h2​=h2+(a/2)2​=82+(10/2)2​=89​ dm≐9.434 dm  S1​=2a⋅ h1​​=210⋅ 8.544​=5 73​ dm2≐42.72 dm2 S2​=2b⋅ h2​​=26⋅ 9.434​=3 89​ dm2≐28.3019 dm2 B=a⋅ b=10⋅ 6=60 dm2  S=2⋅ S1​+2⋅ S2​+B=2⋅ 42.72+2⋅ 28.3019+60=202.0439 dm2

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