Euclid2

In right triangle ABC with right angle at C is given side a=27 and height v=12. Calculate the perimeter of the triangle.

Correct result:

p =  70.5

Solution:

 a=27 v=12  ca=272−122=24.19 cb=122ca=5.95  c=ca+cb=30.14  b=c2−a2=179.42  o=a+b+c=70.5  \ \\ a= 27 \ \\ v = 12 \ \\ \ \\ c_a = \sqrt{ 27^2-12^2} = 24.19 \ \\ c_b = \dfrac{ 12^2 }{ c_a } = 5.95 \ \\ \ \\ c = c_a+ c_b = 30.14 \ \\ \ \\ b = \sqrt{ c^2-a^2} = 179.42 \ \\ \ \\ o = a+b+c = 70.5 \ \\

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