# Triangle ABC

Right triangle ABC with right angle at the C, |BC|=18, |AB|=33. Calculate the height of the triangle hAB to the side AB.

Result

hAB =  15.09

#### Solution:

$a^2 = c_2 c \ \\ c_2 = \dfrac{ 18^2 }{ 33 } = 9.82 \ \\ c_1 = c - c_2 = 33 - 9.82 = 23.18 \ \\ h_{AB} = \sqrt{c_1 c_2} = \sqrt{(33 - \dfrac{ 18^2}{ 33}) \cdot \dfrac{ 18^2}{ 33}} = 15.09$

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