Triangle ABC

Right triangle ABC with right angle at the C, |BC|=18, |AB|=33. Calculate the height of the triangle h_AB to the side AB.

Correct answer:

h_AB =  15.09

Step-by-step explanation:

$$\begin{gathered} a^2=c_{2}c \\ {c}_2={\displaystyle \frac{18^2}{33}}=9.82 \\ {c}_1=c-c_2=33-9.82=23.18 \\ {h}_{AB}=\sqrt{c_1{c}_2}=\sqrt{(33-{\displaystyle \frac{18^2}{33}})\cdot {\displaystyle \frac{18^2}{33}}}=15.09 \end{gathered}$$

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