Volume increase

How many percent will increase in the pool 50 m, width 15m if the level rises from 1m to 150cm?

Result

p =  50 %

Solution:

S=50⋅ 12=600 h1=1 h2=150/100=32=1.5 V1=h1⋅ S=1⋅ 600=600 V2=h2⋅ S=1.5⋅ 600=900 p1=(V2−V1)/V1⋅ 100=(900−600)/600⋅ 100=50 p=(h2−h1)/h1⋅ 100=(1.5−1)/1⋅ 100=50=50%S=50 \cdot \ 12=600 \ \\ h_{1}=1 \ \\ h_{2}=150/100=\dfrac{ 3 }{ 2 }=1.5 \ \\ V_{1}=h_{1} \cdot \ S=1 \cdot \ 600=600 \ \\ V_{2}=h_{2} \cdot \ S=1.5 \cdot \ 600=900 \ \\ p_{1}=(V_{2}-V_{1})/V_{1} \cdot \ 100=(900-600)/600 \cdot \ 100=50 \ \\ p=(h_{2}-h_{1})/h_{1} \cdot \ 100=(1.5-1)/1 \cdot \ 100=50=50 \%

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