Laws

From which law follows directly the validity of Pythagoras' theorem in the right triangle?


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Solution:

c2=a2+b2−2abcos⁡γ  γ=90∘⇒cos⁡90∘=0 c2=a2+b2−2abcos⁡90∘ c2=a2+b2c^2 = a^2 + b^2 - 2ab \cos \gamma \ \\ \ \\ \gamma = 90^\circ \Rightarrow \cos 90^\circ =0 \ \\ c^2 = a^2 + b^2 - 2ab \cos 90^\circ \ \\ c^2 = a^2 + b^2

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Tips to related online calculators
Cosine rule uses trigonometric SAS triangle calculator.
See also our trigonometric triangle calculator.
Pythagorean theorem is the base for the right triangle calculator.

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