Determine 82341

Determine the equation of the circle that is the set of all points of the plane that are twice as far from the point [3,7] as they are from the point [0,1].

Correct answer:

e : 3 x^2 + 6 x + 3 y^2 + 6 y - 54 = 0

Step-by-step explanation:

A=(3,7) B=(0,1)  XA = 2 XB XA2 = 22 XB2 (xAx)2 + (yAy)2 = 4 ((xBx)2 + (yBy)2) (x3)2 + (y7)2 = 4 ((x0)2 + (y1)2) (x26x+9) + (y214y+49) = 4x2 + 4(y22y+1) 3 x2  6 x  3 y2  6 y + 54 = 0 3 x2 + 6 x + 3 y2 + 6 y  54 = 0  e:3 x2+6 x+3 y2+6 y54=0



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